Assume that y varies directly as x. If y = 4 when x = 0.5, find y when x = 2.?
回答 (9)
2008-06-17 3:23 pm
✔ 最佳答案
16 
2008-06-17 11:49 pm
y = k x
4 = 0.5 k
k = 8
y = 8 x
y = (8) (2)
y = 16
4 = 0.5 k
k = 8
y = 8 x
y = (8) (2)
y = 16
2008-06-17 11:10 pm
4/0.5
= 8
When x = 2 , y equals:
8 x 2
= 16
= 8
When x = 2 , y equals:
8 x 2
= 16
2008-06-17 10:35 pm
given y=4 when x=0.5
to know what is the value of y when x=2
multiply both with 4 to make x value 2 x=0.5*4 =2
y=4*4 =16
so when x=2 y=16
to know what is the value of y when x=2
multiply both with 4 to make x value 2 x=0.5*4 =2
y=4*4 =16
so when x=2 y=16
2008-06-17 10:30 pm
y = 4 and x = 0.5
when x = 2,
y = 2/0.5 x 4
y = 20/5 x 4
y = 4 x 4
y = 16
when x = 2,
y = 2/0.5 x 4
y = 20/5 x 4
y = 4 x 4
y = 16
2008-06-17 10:26 pm
2/ .5 = 4
so 4 x 4=16
so 4 x 4=16
2008-06-17 10:26 pm
y varies directly as x.
y=kx, where k is a constant
4=k(0.5)
k= 4 / 0.5
k = 8
y=8x
when x=2,
y=8(2) = 16
y=kx, where k is a constant
4=k(0.5)
k= 4 / 0.5
k = 8
y=8x
when x=2,
y=8(2) = 16
2008-06-17 10:25 pm
y= 16
2008-06-17 10:23 pm
so a direct relationship is y=kx. so you can find out what the ratio is. 4/.5=8. so when x=2 y=16
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