x^2 + 6x + 5
r^2 + 12r + 27
3^2 + 15x + 18
How do I factor these trinomials? Thanks?
2008-06-15 4:22 pm
回答 (3)
2008-06-15 4:27 pm
✔ 最佳答案
(x+5)(x+1)(r+9)(r+3)
the last one isn't a trinomial. it's just 15x + 27. i think you made a typo.
2008-06-15 5:05 pm
1)
x^2 + 6x + 5
= x^2 + x + 5x + 5
= x(x + 1) + 5(x + 1)
= (x + 1)(x + 5)
2)
r^2 + 12r + 27
= r^2 + 3r + 9r + 27
= r(r + 3) + 9(r + 3)
= (r + 3)(r + 9)
3)
3x^2 + 15x + 18
= 3(x^2 + 5x + 6)
= 3(x + 2)(x + 3)
x^2 + 6x + 5
= x^2 + x + 5x + 5
= x(x + 1) + 5(x + 1)
= (x + 1)(x + 5)
2)
r^2 + 12r + 27
= r^2 + 3r + 9r + 27
= r(r + 3) + 9(r + 3)
= (r + 3)(r + 9)
3)
3x^2 + 15x + 18
= 3(x^2 + 5x + 6)
= 3(x + 2)(x + 3)
2008-06-15 4:29 pm
r^2 + 12r + 27
r^2+9r+3r+27
r(r+9)+3(r+9)
(r+9)(r+3)
3x^2+15x+18
3x^2+9x+6x+18
3x(x+3)+6(x+3)
(3x+6)(x+3)
3(x+2)(x+3)
r^2+9r+3r+27
r(r+9)+3(r+9)
(r+9)(r+3)
3x^2+15x+18
3x^2+9x+6x+18
3x(x+3)+6(x+3)
(3x+6)(x+3)
3(x+2)(x+3)
收錄日期: 2021-05-01 10:38:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080615082216AAt1hIo