1. lim n>infinity (1+2+3+..+n)/n^2
Why we can't treat as 1/n^2+ 2/n^2+..+1/n and then equal 0?
2. lim n>infinity (1+1/2+1/4+...+1/2^n)
3. lim x>infinity ( (x^3+x)^1/3 - (x^3+3)^1/3 )
F.4 limit questions
2008-06-15 1:42 am
回答 (1)
2008-06-15 3:35 am
✔ 最佳答案
AS follow~~~~~~~~~!AS follow~~~~~~~~~!
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收錄日期: 2021-04-23 20:36:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080614000051KK01893