Multiply (x+3)(x^2+4x-6)?

(x + 3)(x^2 + 4x - 6)
= x*x^2 + 3*x^2 + x*4x + 3*4x - x*6 - 3*6
= x^3 + 3x^2 + 4x^2 + 12x - 6x - 18
= x^3 + 7x^2 + 6x - 18

i'm assuming that a volume following x is raised to a potential of that quantity so 3x3 might desire to be 3x to a potential of three (or 3x cubed as some human beings call it). i'm additionally assuming that those are surely 2 words in parenthesis. If this is stunning then it would desire to be 9x^5 - 24x^4 - 52x^3 + 48x^2. then in case you pass extra you may desire to element out x squared to get x^2 (9x^3 - 24x^2 - 52x + 40 8) in the journey that they do no longer look in parenthesis then you definately truthfully surely multiply 12x2 and 3x2 to get 36x2 and then there is not extra simplifying you're able to do from there. so as which you may desire to finally finally end up with 3x3 - 36x2 + 4x - 4

(x + 3)(x^2 + 4x - 6)
= x^3 + 4x^2 - 6x + 3x^2 + 12x - 18
= x^3 + 7x^2 + 6x - 18

x³ + 4x² - 6x
___3x² + 12x - 18

x³ + 7x² + 6x - 18

Multiply it one by one. x first then 3

( x^3 + 4x^2 - 6x ) + ( 3x^2 + 12x - 18 ) = x^3 + 7x^2 +6x -18

you distribute the x+3 to every number in the big parentheses
you would get- x^3+4x^2-6x+3x^2+12x-18

then you simplify it by combining like terms
answer- x^3+7x^2+6x-18

x^3+4x^2-6x+3x^2+12x-18
x^3+7x^2+12x-18
i think that is the answer- no clue sorry

x^3+7x^2+6x-18

Multiply x by the (x^2+4x-6) and 3 by the (x^2+4x-6) and simplify!

(x+3)(x^2+4x-6)
=
x (x^2+4x-6) + 3 (x^2+4x-6)
=
x^3 + 4x^2 - 6x + 3x^2 + 12x - 18
= x^3 + 7x^2 + 6x -18

you first multiply all the terms in the second group by x.
you get:
x^3+4x^2-6x
then you multiply each by 3 and add everything together