Help!Math Problem?

x^3 = 64/27 = (4/3)^3
x=4/3

x^-3=27/64
Therefore, ....1/x^3 = 27/64
Hence,....x = cube root of 64 / cube root of 27
x = 4/3.......Thats simple !!

x^-3 = 27/64
1/x^3 = 27/64
x^3 = 1/(27/64)
x^3 = 64/27
x = ³√(64/27)
x = 4/3

x^-3=27/64
=>x^3=64/27
=>x^3=(4/3)^3
=>x=4/3

x=4/3

x^-3 = 27/64
(x^-3)^(-1/3)
= (27/64)^(-1/3)
= [(1/3)/(1/4)]
= 4/3

x^-3 = 27/64

x^-3 = 1/x^3 = 27/64

x^3 = 64/27

x = 4/3 = 1.33333*

if it's to the (-3) power than the answer should be 19683/262144

if it was to the 3rd power the answer is 3/4

lol. wow what are you a rocket scientist!?!?! good luck! i would guess x would be 5