algeeebra .?

1). 12< -3x + 6+5= 12<-3x + 11 = 1< -3x
- 1/3 >x
-3x>27 = > x< -9
x< -1/3 AND X<-9

2). lx-3l + 4 = 15
lx-3l = 11
x-3 = -11 => x= -8
and
x-3 = 11 => x = 14

Question 1
12 < - 3x + 6 + 5
1 < - 3x
3x < - 1
x < - 1/3

-3x > 27
3x < - 27
x < - 9

x < - 9 is required solution.

Question 2
| x - 3 | = 11

x - 3 = 11
x = 14

x - 3 = - 11
x = - 8

x = - 8 , x = 14

yeah.. i beleive the person that answered this is correct:] lol

2.)x=14
1.)

1)
12 < -3(x - 2) + 5 and -3x > 27
12 < -3x + 6 + 5 and x < 27/-3
-3x > 12 - 6 - 5 and x < -9
-3x > 1 and x < -9
x < -1/3 and x < -9

2)
|x - 3| + 4 = 15
|x - 3| = 15 - 4
|x - 3| = 11
x + 3 = ±11

x + 3 = 11
x = 11 - 3
x = 8

x + 3 = -11
x = -11 - 3
x = -14

∴ x = 8 , -14