3x^2+21x= factor?
回答 (11)
2008-06-10 2:51 pm
✔ 最佳答案
3x^2+21x=3x(x+7)
2008-06-10 3:09 pm
= 3x² + 21x
= 3x(x + 7)
Answer: 3x(x + 7)
= 3x(x + 7)
Answer: 3x(x + 7)
2008-06-14 1:47 pm
3x (x + 7)
2008-06-10 3:14 pm
3x^2 + 21x = 3x ( x + 7)
the factors are 3x and (x+7)
the factors are 3x and (x+7)
2008-06-10 3:03 pm
3x(x+7)
=>> x=0,-7
=>> x=0,-7
2008-06-10 2:37 pm
3x^2 + 21x
= 3(x^2 + 7x)
= 3x(x + 7)
= 3(x^2 + 7x)
= 3x(x + 7)
2008-06-10 2:28 pm
Common Monomial Factor:
since 3 and 21 are divisible by 3 and x^2 and x are divisible by x, therefore:
=3x(x+7)
since 3 and 21 are divisible by 3 and x^2 and x are divisible by x, therefore:
=3x(x+7)
參考: My Algebra Book
2008-06-10 2:27 pm
3x^2 + 21x
= 3x(x + 7)
the factor are 3x and (x + 7)
= 3x(x + 7)
the factor are 3x and (x + 7)
2008-06-10 2:27 pm
3x( x+7)
2008-06-10 2:26 pm
= 3x(x + 7)
收錄日期: 2021-05-01 10:35:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080610062313AApv5tT