Machine A can produce (5X+1) toy cars every two hours and machine B can produce (7X+10) toy cars every three hours .If machine A and machine B start opearingat the same time , the number of toy cars produced by the two machine are the same after 6 hours.How many toys cars can be produced in total by the two machine after 6 hours.
點解&點計
MATH F.1
2008-06-10 9:10 pm
回答 (2)
2008-06-10 9:34 pm
✔ 最佳答案
米即係Machine A 每2小時可以生產(5x+1)個公仔,Machine B 每3小時可以生產(7x+10)個公仔
生產6小時後,
Machine A 同Machine B生產既公仔既數量相同
問6小時後2個Machine total 生產左幾多?
(5x+1)(6/2)=(7x+10)(6/3)
15x+3=14x+20
x=17
--------------------------------
(5x+1)(6/2)+(7x+10)(6/3)
=(5(17)+1)(6/2)+(7(17)+10)(6/3)
=516
所以6小時後total生產左516個公仔.
參考: me
2008-06-10 9:24 pm
A machine produce toy for each hr = (5x+1)/2
B machine produce toy for each hr = (7x+10)/3
After 6 hr.
A machine produce toy = (5x+1)/2 * 6
B machine produce toy = (7x+10)/3 *6
the number of toy cars produced by the two machine are the same after 6 hours
(5x+1)/2 * 6 = (7x+10)/3 *6
x = 17
two machine car produce toys after 6 hr. = [(5x+1)/2 * 6] + [(7x+10)/3 *6]
= 258+258 = 516
B machine produce toy for each hr = (7x+10)/3
After 6 hr.
A machine produce toy = (5x+1)/2 * 6
B machine produce toy = (7x+10)/3 *6
the number of toy cars produced by the two machine are the same after 6 hours
(5x+1)/2 * 6 = (7x+10)/3 *6
x = 17
two machine car produce toys after 6 hr. = [(5x+1)/2 * 6] + [(7x+10)/3 *6]
= 258+258 = 516
參考: myself
收錄日期: 2021-04-13 15:40:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080610000051KK00879