factor x^2-13x+42=0?

x^2 - 13x + 32 = 0

(x - 6)(x - 7) = 0.

x = 6 AND x = 7.

-John

x^2 - 13x + 42 = 0
x^2 - 6x - 7x + 42 = 0
(x - 6)(x - 7) = 0

x - 6 = 0
x = 6

x - 7 = 0
x = 7

∴ x = 6 , 7

x²-13x+42 = 0
=> x²-6x-7x+42 = 0
=> x(x-6)-7(x-6) = 0
=> (x-6)(x-7) = 0
=> x = 6, and, x = 7

13 X 42

To factor first set up the equation as ax^2 + bx + c = 0 So x^2 - 13x +42 = 0 Then factor: (x -6) (x - 7) = 0 Solve for x to make equation true x = 6 and x = 7

Question Number 1 :
For this equation x^2 - 13*x + 42 = 0 , answer the following questions :
A. Use factorization to find the root of the equation !

Answer Number 1 :
The equation x^2 - 13*x + 42 = 0 is already in a*x^2+b*x+c=0 form.
So we can imply that the value of a = 1, b = -13, c = 42.

1A. Use factorization to find the root of the equation !
x^2 - 13*x + 42 = 0
( x - 7 ) * ( x - 6 ) = 0
The answers are x1 = 7 and x2 = 6

(x-6)(x-7)=0

x=6 and 7

(x - 7)(x - 6) = 0
x = 7 , x = 6

x^2-13x+42=0
=>x^2-7x-6x+42=0
=>x(x-7)-6(x-7)=0
=>(x-7)(x-6)=0
hence (x-7)=0 and (x-6)=0
x=7 and x=6