how to do this sum: (x+4)(x+10)?

Multiply every term by every other term:

(x + 4)(x + 10) =

x^2 + 10x + 4x + 40 =

Answer: x^2 + 14x + 40.

-John

The answer is 2x x 14.

x^2+4x+10x+40
x^2+14x+40

x² + 10x + 4x + 40
x² + 14x + 40

Use the FOIL Method to multiply:

First x * x = x^2
Outer x * 10 = 10x
Inner 4 * x = 4x
Last 4 * 10 = 40

x^2 + 10x +4x + 40

Now combine like terms:

x^2 + 14x + 40

(x + 4)(x + 10)
= x × x + 4 × x + x × 10 + 4 × 10
= x² + 4x + 10x + 40
= x² + 14x + 40
---------

(x + 4)(x + 10)
= x*x + 4*x + x*10 + 4*10
= x^2 + 4x + 10x + 40
= x^2 + 14x + 40

x*(x+10)+4*(x+10)

= x^2+10x + 4x+ 40

= x^2+14x+40