factor 4y^2-100=0?

4y^2 - 100 = 0.

(2y - 10)(2y + 10) = 0.

2y - 10 = 0 AND 2y + 10 = 0.

y = 5 AND y = -5.

-John

Hi,

For this question, let's first add 100 to both sides of the equation to get:

4y^2 = 100

Now, divide both sides by 4 to get the variable y alone to get:

y^2 = 25

At this point, we need to get the variable y alone (just y) by taking the square root of both sides. When we take the square root, we will be getting both a positive and negative root because when squaring these values, we will get positive 25 back!

Therefore, our final answers for this problem are:

y = 5

AND. . . .

y = -5

I hope that helps you out! Please let me know if you have any other questions!

4y² = 100
y² = 25
y = ± 5

4y^2-100=0

4(y^2-25)=0

4(y-5)(y+5)=0

y=-5 and 5

4y² – 100 = 0
4y² = 100
y² = 25
y = √25
y = ± 5
----------

4y^2 - 100 = 0
(4y^2 - 100)/4 = 0/4
y^2 - 25 = 0
(y + 5)(y - 5) = 0

y + 5 = 0
y = -5

y - 5 = 0
y = 5

∴ y = ±5

4y^2-100=0
=>y^2-25=0[dividing both sides by 4]
=>y^2=25
=>y=+-5

Common factor of 4, then a difference of two squares...


4y^2 - 100 = 0
4(y^2 -25) = 0
4(y + 5)(y -5) = 0

That is factorised are you supposed to solve it too?

If so,

y + 5 = 0 or y - 5 = 0
y = -5 or y = 5

4y^2-100 = 0

divide by 4

y^2-25=0

y^2=25

Y=+5, -5