Ice cubes of 25g at 0oC are dropped into a breaker containing 250g of water at 30oC . What is the final temperature of the mixture? Assume no energy is lost to the surroundings.
as theyre both water...do we need to involve the mass?
F.3 phy,,,final temperature of mixture///
2008-06-10 5:27 am
回答 (2)
2008-06-10 9:06 am
✔ 最佳答案
yes energy lost by water = energy gain by ice
mc△T of water= (mc△T + ml) of ice
0.25x4200x(30-T) = 0.025x4200x(T-0) + 0.025x3.34x10^5
31500 - 1050T = 105T + 8350
1155T = 23150
T= 20.04oC
It will become 20.04oC of water
參考: me
2008-06-10 6:03 am
the equation :
the energy lost by the 250g water = the energy absorded by the 25g ice cubes
0.25 (4200) (30 -- t) = 0.025 (3.34 X 10^5) + 0.025(4200)t
--1050t + 31500 = 8350 + 105t
t = -20.04 degree centigrade
It means the fusion of ice cubes is not complete.
the energy lost by the 250g water = the energy absorded by the 25g ice cubes
0.25 (4200) (30 -- t) = 0.025 (3.34 X 10^5) + 0.025(4200)t
--1050t + 31500 = 8350 + 105t
t = -20.04 degree centigrade
It means the fusion of ice cubes is not complete.
收錄日期: 2021-04-13 15:40:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080609000051KK03002