math f1 (20點) 邊個解得詳細就邊個攞果20點!

2008-06-09 10:00 pm
Machine A can produce (5X+1) toy cars every two hours and machine B can produce (7X+10) toy cars every three hours .If machine A and machine B start opearingat the same time , the number of toy cars produced by the two machine are the same after 6 hours.How many toys cars can be produced in total by the two machine after 6 hours.

點解&點計

回答 (2)

2008-06-09 10:16 pm
✔ 最佳答案
Production Rate of Machine A (toy car/hour) is:
(5x+1)/2

Production Rate of Machine B (toy car/hour) is:
(7x+10)/3

Number of toy car after 6 hours of Machine A=Number of toy car after 6 hours of Machine B

i.e., 6*[(5x+1)/2] = 6*[(7x+10)/3]
15x+3 = 14x+20
x=17

So, toys cars can be produced in total by the two machine after 6 hours is
6*[(5x+1)/2] + 6*[(7x+10)/3] for x=17
29x+23=516

HENCE, ANSWER IS 516.
2008-06-10 9:16 pm
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