it is larger and decrease bounds i take it. basically the decrease sure is the minimum attainable value it is so as that as quickly as you around the minimum value it equals the given value which subsequently is 3ft or 5ft. decrease sure of 3ft = 2.5ft decrease sure of 5ft = 4.5ft So the backside area is lowest bounds of three and 5 expanded. 2.5ft x 4.5ft = 11.25ft optimal area is upperbound x upperbound that's: UB of 3ft = 3.5 (easily 3.49999999 - yet in truth comparable difficulty) UB of 5ft= 5.5 optimal area = 3.5 x 5.5= 19.25ft
I think you have problem with the operational sines. You have shown division, it should be multiplication or you do need to correct other components of the statements.
But if you mean two third meters and two fifth meters sides then it is 4/15 Sq. meters =.26666-- or .267(3 significant fig).