F.2數學((6(x-A)+3≡3(Bx-1)求常數A和B的值 )

👨🏻‍🏫 學術台數學

WIEEIN

2008-06-09 7:28 am

6(x-A)+3≡3(Bx-1)求常數A和B的值

回答 (3)

用戶7639

2008-06-16 10:40 pm

✔ 最佳答案

左方=6(x-A)+3
=6x+(3-6A)
右方=3(Bx-1)
=3BX-3
比較左方和右方同類項可得,
3B=6_________(1)
3-6A=-3_______(2)
從(1)可得:
B=2
從(2)可得:
A=1

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Wan Chak

2008-06-09 8:55 am

6(x-A)+3≡3(Bx-1)
6x - 6A + 3 ≡ 3Bx - 3
6x - 6A ≡ 3Bx - 6
By comparing coefficient,
6x = 3Bx
B = 2//
-6A = -6
A = 1//

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[匿名]

2008-06-09 7:40 am

6x-6A≡3Bx-3
by comparing coefficient,
6=3B
-6A=-3
so, A=0.5 , B=2

參考: 自己

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