F.2數學((6(x-A)+3≡3(Bx-1)求常數A和B的值 )

左方=6(x-A)+3
=6x+(3-6A)
右方=3(Bx-1)
=3BX-3
比較左方和右方同類項可得,
3B=6_________(1)
3-6A=-3_______(2)
從(1)可得:
B=2
從(2)可得:
A=1

6(x-A)+3≡3(Bx-1)
6x - 6A + 3 ≡ 3Bx - 3
6x - 6A ≡ 3Bx - 6
By comparing coefficient,
6x = 3Bx
B = 2//
-6A = -6
A = 1//

6x-6A≡3Bx-3
by comparing coefficient,
6=3B
-6A=-3
so, A=0.5 , B=2