a-maths~!

先找出slope為0的點：
f'(x)=60x5-120x4 60x3
Set f'(x)=0
60x5-120x4 60x3=0
60x3(x2-2x 1)=0
x3=0 or x2-2x 1=0
x=0 or 1
(所以在x=0或1時，曲線的slope是0)
再找出f(0)和f(1)的值
f(0)=0
f(1)=1
所以函數f(x)的相對極值是0和1

http://i117.photobucket.com/albums/o61/billy_hywung/May08/Crazydiff1-1.jpg