Find the optium values of the following functions
1)y=(x=1)(x-7) + 3
2)y=x(8-x) + 10
Give me step plz^_^
F.4 maths
2008-06-08 4:46 pm
回答 (1)
2008-06-08 5:04 pm
✔ 最佳答案
我真係唔建議俾晒step你...我做第一條俾你睇睇啦
1) y=(x+1)(x-7)+3, 爆開佢先
y=x^2-6x-4, 然後就completing the square
y=(x^2-6x+9-9)-4
y=(x-3)^2-13
由於x^2既coefficient係正數,所以只會有minimum value
so the minimum value of the given function is -13.
第二題比第一題容易,所以我想你自己試試做
hint: 記住completing the square果陣coefficient of x^2一定要係正數加油啦 ^^
參考: 本人是應屆會考生
收錄日期: 2021-04-13 15:40:32
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