Math help again?

2008-06-07 3:03 pm
sorry im asking so many questions. i have to take a math final next week and im studying for it.
heres the problem:
subtract:
(4m^2-6m+1) - (2m^2+4m-3)

回答 (4)

2008-06-07 3:31 pm
✔ 最佳答案
(4m^2 - 6m + 1) - (2m^2 + 4m - 3)
= 4m^2 - 6m + 1 - 2m^2 - 4m + 3
= 4m^2 - 2m^2 - 6m - 4m + 1 + 3
= 2m^2 - 10m + 4
2008-06-07 10:14 pm
(4m^2-6m+1) - (2m^2+4m-3)
= 4m^2-6m+1-2m^2-4m+3
= 2^m-10m+4
2008-06-07 10:07 pm
(4m^2-6m+1) - (2m^2+4m-3) = 2m^2 -10m + 4
2008-06-07 10:07 pm
4m^2-6m+1 -2m^2-4m+3 (distributed the negative sign)

2m^2-10m+4 is your answer.


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