The question is shown in the following link:
http://i256.photobucket.com/albums/hh172/hkchelsea_united/question080607.png
Thanks a lot!
Pure Mathematics - Integration
2008-06-07 1:06 pm
回答 (2)
2008-06-07 1:51 pm
✔ 最佳答案
x=ln(t-1)^0.5differentiate both side with respect to t
LHS=dx/dt
RHS=[1/(t-1)^0.5]*(t-1)^-0.5*1/2=1/[2(t-1)]
therefore dx=1/[2(t-1)]*dt
then replace x in term of t in the question
dx=1/[2(t-1)]*dt
then the question become 1/2︴(t-1)t^1/3 dt
=1/2︴t^4/3 dt - 1/2︴t^1/3dt
done
︴=integration
2008-06-12 10:03 pm
收錄日期: 2021-04-13 15:39:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080607000051KK00388