三角形底面積?

2008-06-07 3:27 am
係一個直角三角形ABC
AB=10cm,BC=8
我想要佢個高黎搵底面積
但吾識計-v-
please help!!!

回答 (7)

2008-06-11 9:33 am
✔ 最佳答案
there are 2 answers

1: AB is the longest side
AC² = 10² - 8²
AC = 6cm
(6 x 8) / 2
= 24cm²

2: AC is the longest side
(10 x 8) / 2
= 40cm²

thus the area = 24 or 40 cm²
參考: me
2008-06-07 3:48 am
Use Pyth. theorem
Height =10²-8²=6²
∴Area=8*6/2=24cm²

2008-06-06 19:49:02 補充:
It should be Height =sqrt(10²-8²)=6

2008-06-06 19:49:52 補充:
佢講得好清楚喎
話明搵高姐係AB同BC都唔係高啦~
2008-06-07 3:40 am
直角三角形的計方法 :

張個角架lay2條邊X埋隨2

你條問題的算息:

10cmX8cm隨2

=40(平方厘米)
參考: me
2008-06-07 3:38 am
step1: 低邊除以2 =4
step2: ab的2次方-4的2次方
=100-16(畢氏定理)
=開方根 84
=大約高係9.165
2008-06-07 3:36 am
用畢氏定理黎揾埋另一條邊~
條公式係咁既~
斜邊既平方=邊1既平方 邊2既平方
咁就可以揾到果個高喇~
跟住個底面積你識計喇~
條公式係:
底x高
一一一
2
參考: 自己
2008-06-07 3:36 am
if you don't know how to find the height of the triangle
you can use 畢氏定理 to find it
AC=(10^2-8^2)^1/2
AC=6
area of triangle=6x8/2=24
2008-06-07 3:33 am
你都未講邊隻角係正角..
計唔到bor


收錄日期: 2021-04-26 16:08:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080606000051KK02181

檢視 Wayback Machine 備份