✔ 最佳答案
According you answer,I think the temperature of the mixture should be 60度.
Let the the initial mass of the hot coffee in the cup be m kg,
By the law of conservation of energy,
energy released by hot coffee = energy absorbed by milk
(mc) (c)Δ(Tc﹣T) = (mm) (c)Δ(T ﹣Tm)
m(4000)(80﹣60) = (0.1)(3800)(60﹣20)
m(4000)(20) = (0.1)(3800)(40)
80000m = 15200
m = 0.19kg
∴ the the initial mass of the hot coffee in the cup is 0.19kg.
2008-06-06 19:21:25 補充:
According your answer
2008-06-06 19:22:18 補充:
Assume that no energy lost to the surrounding
2008-06-06 19:26:45 補充:
中文:你所說的混合溫度是604度是錯誤的,因為一杯80度的和20度的液體,混合的溫度是介乎20和80度之間。
2008-06-06 20:11:37 補充:
sorry for some errors,it should be
(m)(c)(Tc﹣T) = (m)(c)(T ﹣Tm)