Solve this equation by factoring?

140x^2 + 300x = -40x - 120
140x^2 + 340x + 120 = 0
7x^2 + 17x + 6 = 0 (Dividing both sides by 20)
7x^2 + 14x + 3x + 6 = 0
7x(x + 2) + 3(x + 2) = 0
(7x + 3)(x + 2) = 0

Setting each factor to 0,
x = -3/7, -2

140x² + 300x = - 40x - 120
7x² + 15x = - 2x - 6
7x² + 17x + 6 = 0

Factors:
(7x + 3)(x + 2) = 0

Values of x:
7x + 3 = 0
7x = - 3
x = - 3/7

x + 2 = 0
x = - 2

Answer: x = - 3/7, x = - 2

Proof:
140(- 3/7)² + 300(- 3/7) = - 40(- 3/7) - 120
140(9/49) - 900/7 = 120/7 - 120
1,260/49 - 6,300/49 = 120/7 - 840/7
- 5,040/49 = - 720/7
- 720/7 = - 720/7

Proof:
140(- 2)² + 300(- 2) = - 40(- 2) - 120
140(4) - 600 = 80 - 120
560 - 600 = - 40
- 40 = - 40

x^2 + 5x - 14 = 0 14 may be produced by utilising multiply a million and 14 jointly, and a pair of and seven jointly. you % to % the two numbers in spite of the undeniable fact that that would provide you 5 by utilising the two including them of subtracting them from one yet another. for this reason, it quite is 2 and seven. for this reason: (x-2)(x+7) = x^2 + 7x - 2x - 14 = x^2 + 5x -14. Now (x-2)(x+7) will equivalent 0 while the two (x-2) = 0 and/or (x+7) = 0. (x-2) = 0 --> x = 2 (x+7) = 0 --> x = -7 for this reason, you solutions are: x = -7, 2 desire this enables :)

14x² + 34 x + 12 = 0
7x ² + 17x + 6 = 0
(7x + 3)(x + 2) = 0
x = - 3/7 , x = - 2

140x^2 + 300x = -40x - 120
140x^2 + 340x = - 120
140x^2 + 340x + 120 = 0
7x^2 + 17x + 6 = 0

(ax + b)(x + c) = 0
a*x^2 + ac*x + b*x + b*c = 0
Let a = 7, b = 3, c = 2
(7x + 3)(x + 2) = 0

Case 1:
7x + 3 = 0
7x = -3
x = -3/7

Case 2:
x + 2 = 0
x = -2

Therefore, x = -2, -3/7

140x^2 + 300x = -40x-120

Divide by 10 both the sides

14x^2+30x = -4x-12

bring it all to left side equating for zero

14x^2+30x+4x+12 = 0

14x^2+34x+12 = 0

Divide by 2

7x^2+17x+6 = 0

This can also be written as

7x^2+14x+3x+6=0

7x(x+2) + 3(x+2) = 0

(7x+3) (x+2) = 0
when 7x+3 = 0
x = -3/7

when x+2 = 0
x = -2

140x2 + 300x2 = -40x -120
140x2 + 340x + 120 = 0
( 70x + 30)(2x + 4) = 0
70x + 30 = 0 2x + 4 = 0
70x = -30 2x = -4
x= -3/7 x = -2

Reduce it into

7x^2 + 17x + 6=0

Now by splitting the middle term
7x^2 + 14x + 3x + 6= 0

7x (x+2) 3(x+2)= 0

(7x +3) (x+2) = 0

x = -3/7 OR x = -2

140x^2 + 300x = -40x - 120
140x^2 + 300x + 40x + 120 = 0
140x^2 + 340x + 120 = 0
(140x^2 + 340x + 120)/20 = 0/20
7x^2 + 17x + 6 = 0
(7x + 3)(x + 2) = 0

7x + 3 = 0
7x = -3
x = -3/7

x + 2 = 0
x = -2

∴ x = -3/7 , -2

140x^2 + 300x = -40x -120

140x^2 + 300x +40X +120 =0

140x^2 + 340x +120 =0

14x^2 +34x+12 = 0

(2x + 6 )(7x +2) =0 (not correct)

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