Math question(S2)

1.Let the smaller consecutive multiples of 5 is x.
The bigger one is x+5

x小於(x+5)/2
2x小於x+5
x小於5

so the least values of these two number are 10 and (10+5)=15.

2.x大於y+5...(1)
x+y小於49...(2)
From(1), y小於x-5
Sub (1) into (2), x+x-5小於49
2x小於54
x小於27

so the largest value of x is 26.

第一條唔知
第二條X係27 Y係21 可能唔對

1 let the two number be x and x+1
5x>(x+1)*5 / 2
5x>2.5x+2.5
2.5x>2.5
x>1
the least values of these two number are 2 and 3 (2+1)

2, x = y+5,代入xy<49
(y+5)*y <49
y<5
the largest value of x is 4

2008-06-05 19:46:05 補充：
> 等於大於
< 等於小於

2008-06-05 19:46:55 補充：
>等於大於
<等於小於

顯示唔到