找t 請列式
-100 = 50t- (0.5)(9.8)(t^2)
help 簡單數學
2008-06-04 10:08 pm
回答 (2)
2008-06-04 10:13 pm
✔ 最佳答案
-100 = 50t- (0.5)(9.8)(t^2) 4.9t^2 -50t - 100 =0
t= [50+/-sqrt(50^2+4*4.9*100)]/2*4.9
t= 50+66.7832314282/9.8 or 50-66.7832314282/9.8
t= 11.9166562681 or t= -1.71257463553
2008-06-08 11:09 pm
-100 = 50t- (0.5)(9.8)(t^2)
4.9t^2 -50t - 100 =0
t= [50+/-sqrt(50^2+4*4.9*100)]/2*4.9
t= 50+66.7832314282/9.8 or 50-66.7832314282/9.8
t= 11.9166562681 or t= -1.71257463553
4.9t^2 -50t - 100 =0
t= [50+/-sqrt(50^2+4*4.9*100)]/2*4.9
t= 50+66.7832314282/9.8 or 50-66.7832314282/9.8
t= 11.9166562681 or t= -1.71257463553
參考: me
收錄日期: 2021-04-15 15:20:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080604000051KK00974