How simplify 8(2x+5) - 7(x-9)?

8(2x+5) - 7(x-9)
= 16x + 40 - 7x + 63
= 9x + 103

= 8(2x + 5) - 7(x - 9)
= 16x + 40 - 7x + 63
= 9x + 103

Answer: 9x + 103

1)
8(2x + 5) - 7(x - 9)
= 8*2x + 8*5 - 7*x + 7*9
= 16x + 40 - 7x + 63
= 16x - 7x + 40 + 63
= 9x + 103

2)
2(2 - 5t) + t^2(t - 1) - (t^4 - 1)
= 2*2 - 2*5t + t^2*t - t^2*1 - t^4 + 1
= 4 - 10t + t^3 - t^2 - t^4 + 1
= -t^4 + t^3 - t^2 - 10t + 1 + 4
= -t^4 + t^3 - t^2 - 10t + 5

Multiply everything inside the brackets by the number outside:
8(2x + 5) - 7(x - 9)
= 16x + 40 - 7x + 63 (it is -7 do not forget)

Next collect the like terms and add together:
16x + 40 - 7x + 63
= (16x - 7x) + (40 + 63)
= 9x + 103

2(2 - 5t ) + t^2 (t - 1) - (t^4 - 1)
= 4 - 10t + t^3 - t^2 - t^4 + 1
= -t^4 + t^3 - t^2 - 10t + 5


:: am i good. hehehe!

1.
16x+40-7x+63
=9x+103

2.
4-10t+t^3-t^2-t^4+1
=-t^4+t^3-t^2-10t+5

Multiply everything inside the brackets by the number outside:
8(2x + 5) - 7(x - 9)
= 16x + 40 - 7x + 63 (it is -7 do not forget)

Next collect the like terms and add together:
16x + 40 - 7x + 63
= (16x - 7x) + (40 + 63)
= 9x + 103

2(2 - 5t ) + t^2 (t - 1) - (t^4 - 1)
= 4 - 10t + t^3 - t^2 - t^4 + 1
= -t^4 + t^3 - t^2 - 10t + 5

*βω*

8(2x+5) - 7(x-9) =

(16x + 40) + (-7x + 63) =

(16x - 7x) + (40 + 63) =

9x + 103

16x +40 -7x +63= 9x+103

Expand the brackets so
8(2x + 5) - 7(x-9) =
16x + 40 - 7x +63 =
9x +103

16x+40 -7x+63
= 9x + 103