1.log25/log 3^√5
2.[sin^2(90°-θ)/sin(180°+ θ) ] + [cos(360°-θ)/tan(180°+θ)]
F.4 LOG(easy)&SIN COS TAN
2008-06-03 9:12 am
回答 (1)
2008-06-03 3:33 pm
✔ 最佳答案
Q.1.log25/log5^(1/3) = log5^2/log5^(1/3) = 2log5/(1/3log5) = 2/(1/3) = 6.
Q.2
tan(180 + x) = tanx ( not -tanx). Therefore, the answer should be 0.
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