小六簡單數學~~~
回答 (8)
2008-06-03 5:16 pm
✔ 最佳答案
運輸車的半徑是:(62.8/3.14)/(50*2)*100
=0.20*100
=20(cm)
2008-06-07 13:21:50 補充：
另一方法:設運車的半徑是rcm,
2(3.14)(r)=62.8*100/50
6.28r=6280/50
6.28r=125.6
r=20
所以運輸車的半徑為20cm.
2008-06-04 8:51 am
同學你打左字...
係運輸車
唔係運偷車"
係運輸車
唔係運偷車"
2008-06-04 4:14 am
運偷車輪的半徑是:
62.8x100/50/3.14/2
=6280/50/3.14/2
=125.6/3.14/2
=40/2
=20厘米
62.8x100/50/3.14/2
=6280/50/3.14/2
=125.6/3.14/2
=40/2
=20厘米
2008-06-03 6:40 am
2r(3.14)(50)=6280
2r(3.14)=6280/50
2r(3.14)=125.6
2r=125.6/3.14
2r=40
r=20
2r(3.14)=6280/50
2r(3.14)=125.6
2r=125.6/3.14
2r=40
r=20
2008-06-03 6:39 am
由於圓周為２ｒｘ３．１４～所以２ｒｘ３．１４＝６２．８／５０
ｒ＝０．２（二位有效ｘ字）
ｒ＝０．２（二位有效ｘ字）
2008-06-03 6:36 am
運輸車輪的半徑：62.8 x 100 / 50 / 3.14 / 2
= 20 厘米
= 20 厘米
2008-06-03 6:33 am
62.8/50
3.14r*r==62.8/50
3.14r*r==62.8/50
收錄日期: 2021-04-13 15:38:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080602000051KK02905