有關Amaths的直線族問題

2008-06-02 10:10 pm
given two straight line:
Ax+By+C1=0-----------------(I)
A2x+By+C2=0----------------(II)

Then,family of straight line passing through two intersection lines=
(Ax+By+C1)+k(A2x+B2y+C2)=0

點解???
我知道點解個family=0
但係點解兩條equation加埋會係個family?
更新1:

咦,照你咁講 L^2 +kM = 0 or L^2 +kM^2 = 0 兩個都唔係直線?

回答 (2)

2008-06-06 9:06 am
✔ 最佳答案
首先我地先prove左existance part先
http://i299.photobucket.com/albums/mm309/lokwanshan/ScreenHunter_06Jun060053.gif

所以條式係可以通過個interception point
但係...係咪所有既線都可以用條式表示呢
定係條式淨係可以show到某幾條既線呢
跟住我地就prove下
http://i299.photobucket.com/albums/mm309/lokwanshan/ScreenHunter_07Jun060104.gif
由此可以知道
所有線都satisfy果條式

2008-06-06 04:21:46 補充:
L係代表Ax+By+C
L^2=(Ax+By+C)^2
=A^2x^2+B^2y^2+2ABxy+......
當然唔係直線啦
L^2係conics,即係parabola,ellipse果d
而係邊種就要睇返ABC係咩喇~
參考: me
2008-06-03 12:04 am
Let the two lines be L=0 and M=0. The intersecting point will satisfy L= 0 and will satisfy M = 0 individually, therefore, it will also satisfy L +kM = 0 for any values of k. Therefore, L +kM= 0 will be the family of straight lines passing through the intersecting point.

2008-06-02 16:11:07 補充:
Since k is a number (positive or negative), L + kM = 0 is still an equation of a straight line.

2008-06-02 16:20:38 補充:
You can argue why the family is L +kM = 0 and not L^2 +kM = 0 or L^2 +kM^2 = 0 etc. since the intersecting point also satisfies them. This is because only L +kM = 0 is a straight line, others are not straight lines.


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