8-4x
______
2x^2 + 3x- 14
How do you Simplify this?
2008-05-31 4:33 pm
回答 (8)
2008-05-31 4:40 pm
✔ 最佳答案
= -4(-2+x)/[(2x+7)(x-2)= -4/(2x+7)
2008-05-31 11:37 pm
factorise first
-4(x - 2)
-----------
(2x+7)(x-2)
cancel x-2
-4 / (2x+7)
-4(x - 2)
-----------
(2x+7)(x-2)
cancel x-2
-4 / (2x+7)
2008-05-31 11:37 pm
you take the sneeze root of x and eat it with tacos
2008-05-31 11:37 pm
-4(x-2)/(2x+7)(x-2)
=-4/(2x-7)
=-4/(2x-7)
2008-05-31 11:40 pm
U have to factorise top and below.
If u factorise the term below (2x^2 ....), u should be able to get (2x+7)(x-2).U should also get 4(2-x) for the term at the top.
4(2-x) = -4(x-2)
Answer:
-4
_____
(2x+7)
If u factorise the term below (2x^2 ....), u should be able to get (2x+7)(x-2).U should also get 4(2-x) for the term at the top.
4(2-x) = -4(x-2)
Answer:
-4
_____
(2x+7)
2008-05-31 11:37 pm
2(2-x)/((2x+7)(x-2))=-2/(2x+7)
2008-06-01 12:52 am
(8 - 4x)/(2x^2 + 3x - 14)
= 4(2 - x)/(-2x - 7)(2 - x)
= 4/(-2x - 7)
= 4(2 - x)/(-2x - 7)(2 - x)
= 4/(-2x - 7)
收錄日期: 2021-05-01 10:33:11
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