-15x +8= -15x-7; x=?
2008-05-31 9:30 am
I've been taught just to add the opposite integer times x of the number multiplied by the variable on one side to the other side, but in this case there would be no x, so is it just trial and error with a graph?... Wait a minute....is the problem impossible to solve?
回答 (5)
2008-05-31 9:39 am
✔ 最佳答案
there is no solution(unless you can get 8 to equal -7)
2008-05-31 5:06 pm
-15x + 8 = -15x - 7
-15x + 15x = -8 - 7
0 = -15
(no solution)
-15x + 15x = -8 - 7
0 = -15
(no solution)
2008-05-31 4:43 pm
There is maybe a mistake somewhere. The equality is false. There is no point in seeking a value of x that satisfies a false statement.
To see this, let minus fifteen x be simply represented by ? and we have
? + 8 = ? - 7.
Removing the question mark from both sides will not change the balance (or imbalance), and we get
+8 = -7
which is false in our ordinary number system. (I presume that you are not working with a finite set of equivalence classes modulo a base, or you would have asked your question differently).
To see this, let minus fifteen x be simply represented by ? and we have
? + 8 = ? - 7.
Removing the question mark from both sides will not change the balance (or imbalance), and we get
+8 = -7
which is false in our ordinary number system. (I presume that you are not working with a finite set of equivalence classes modulo a base, or you would have asked your question differently).
2008-05-31 4:39 pm
-15x+15x=-7-8
0=-15 FALSE
No solution
0=-15 FALSE
No solution
2008-05-31 4:55 pm
-15x+15x=-7-8
x=-15
x=-15
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