更新1:
約簡
MATHS(好易)
回答 (1)
2008-05-31 8:25 pm
✔ 最佳答案
If I understand correct, following is the expression:[x^-2 - (-y)^-2]^-1
= 1/[1/x^2 - 1/(-y)^2]
=1/[1/x^2 - 1/y^2]
=1/[(y^2 - x^2)/x^2y^2]
=x^2y^2/(y^2 - x^2)
收錄日期: 2021-04-25 22:36:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080531000051KK00920