中四數學高手請入

2008-05-29 6:19 am
解聯立方程 ,要點做?
x^2 + y^2 =c^2 (C為常數)

x + y = c


答案(x=0 , y =0 ,y=c ,x=c)

要過程 !!!

回答 (4)

2008-06-04 12:01 am
✔ 最佳答案
x^2 + y^2 = c^2
x^2 + 2xy + y^2 -2xy = c^2
(x + y)^2 -2xy = c^2
c^2 - 2xy = c^2 since x + y = c
2xy = 0
So, x = 0 or y = 0
When x = 0, y^2 = c^2
y = +/- c;
When y = 0, x^2 = c^2
x = +/- c

2008-06-05 16:38:29 補充:
x^2 + y^2 = c^2
x^2 + 2xy + y^2 -2xy = c^2
(x + y)^2 -2xy = c^2
c^2 - 2xy = c^2 since x + y = c
2xy = 0
So, x = 0 or y = 0
When x = 0, y^2 = c^2
y = +/- c;
When y = 0, x^2 = c^2
x = +/- c

2008-06-05 16:38:36 補充:
x^2 + y^2 = c^2
x^2 + 2xy + y^2 -2xy = c^2
(x + y)^2 -2xy = c^2
c^2 - 2xy = c^2 since x + y = c
2xy = 0
So, x = 0 or y = 0
When x = 0, y^2 = c^2
y = +/- c;
When y = 0, x^2 = c^2
x = +/- c
2008-05-29 8:45 pm
x^2 + y^2 = c^2 -------------(1)
x +y = c ----------------------(2)

代 (2) 入 (1) ,
x^2 + y^2 = (x+y)^2
x^2 + y^2 = x^2 + 2xy + y^2
0 = 2xy
x = 0 OR y = 0

代 x = 0 入 (1) ,
y = c

代 y = 0 入 (1) ,
x = 0

所以 , 當 x=0 , y=c ; 當y=0 , x=c
參考: me & truth
2008-05-29 6:31 am
首先, 你俾嘅答案已經好有問題:
y=c ,x=c
既然x + y = c, 咁如果x=y=c, 加埋就係x+y=2c,
除非c=0, 如果唔係個答案就唔成立啦
2008-05-29 6:30 am
x^2 + y^2 = c^2
x^2 + 2xy + y^2 -2xy = c^2
(x + y)^2 -2xy = c^2
c^2 - 2xy = c^2 since x + y = c
2xy = 0
So, x = 0 or y = 0
When x = 0, y^2 = c^2
y = +/- c;
When y = 0, x^2 = c^2
x = +/- c


Finished, thank you~~~


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