數學分數方程ｘ１，極急！！！！！！！

[(x+5)/(2+1/2)] - [(x-1)/(3+1/3)] = 1

[(x+5)/(5/2)] - [(x-1)/(10/3)] = 1

[(2x+10)/5] - [(3x-3)/10] = 1


2(2x+10) - (3x-3)
--------------------- = 1 (通分母)
10

4x+20-3x+3 = 10

x+23 = 10

x = -13


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驗證


[(-13+5) / (5/2)] - [(-13-1)(10/3)]

= [(-8)(2)]/5 - [(-14)(3)/10

= -16/5+42/10

= [(2)(-16)+42]/10

= (-32+42)/10

= 10/10 = 1

2008-05-28 18:35:48 補充：
上面驗證的第2行是
= [(-8)(2)]/5 - [(-14)(3)/10] 漏了個 ]

(x+5)/(2+1/2) - (x-1)/(3+1/3) = 1
(x+5)/(5/2) - (x-1)/(10/3) = 1
(2x+10)/5 - (3x-3)/10 = 1
2(2x+10) - (3x-3) = 1
4x+20-3x+3 = 10
x+23 = 10
x = -13

____________-__________=1

___1___1
=３3-２2=1