dy/dx (x^2-2x+6)^3 (x^2+4x-5)^4

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佢地唔會教你的

Let y= (x^2-2x+6)^3 (x^2+4x-5)^4
By Product and Chain Rule:

dy/dx = 3(x^2-2x+6)^2 * (2x-2) * (x^2+4x-5)^4 + (x^2-2x+6)^3 * 4(x^2+4x-5)^3 * (2x +4)

=(x^2-2x+6)^2(x^2+4x-5)^3 * [6(x-1)(x^2+4x-5) + 8(x^2-2x+6)(x+2) ]
=(x^2-2x+6)^2(x^2+4x-5)^3 * 2[7x^3 + 8x^2 -19x + 63]