1/2(y+4)=y+1/8(4-y)
點計
列晒所有步驟
f.1 math 一條
2008-05-27 3:41 am
回答 (4)
2008-05-27 3:44 am
✔ 最佳答案
1/2(y+4)=y+1/8(4-y)y/2+2=y+1/2-y/8
4y+16=8y+4-y
4y+16=7y+4
12=3y
y=4
參考: my maths knowledge
2008-05-28 3:57 am
1/2(y+4)=y+1/8(4-y)
y/2+2 =y+y/2-y/8
2-y/2=y-y/8-4/8y
1.5=3/8y
3/2*8/3=y
4=y
y=4
y/2+2 =y+y/2-y/8
2-y/2=y-y/8-4/8y
1.5=3/8y
3/2*8/3=y
4=y
y=4
2008-05-27 4:05 am
y/2+2=y+1/2-y/8
y/2-y+y/8=1/2-2
-y/2+y/8=-3/2
-3y/8=-3/2
3y/4=3
3y=12
y=4
y/2-y+y/8=1/2-2
-y/2+y/8=-3/2
-3y/8=-3/2
3y/4=3
3y=12
y=4
參考: me
2008-05-27 3:47 am
1/2(y+4)=y+1/8(4-y)
0.5(y+4)=0.125(4-y)
0.5y+2=0.5-0.125y
0.5y+0.125y=0.5-2
0.625y=-1.5
y=-2.4
y=-12/5
0.5(y+4)=0.125(4-y)
0.5y+2=0.5-0.125y
0.5y+0.125y=0.5-2
0.625y=-1.5
y=-2.4
y=-12/5
參考: me
收錄日期: 2021-04-23 20:44:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080526000051KK02310