[數學]三角題~請大家帮帮忙
回答 (3)
2008-05-26 5:44 am
LINE 2x-3y+5=0
m =2/3
so m of L =-3/2
y/(x-2) = -3/2
2y=6-3x
3x+2y-6=0
2008-05-25 21:47:18 補充：
001運算錯誤~
002 找c 可省 他用 slope- intercept form
我用point slope form
m =2/3
so m of L =-3/2
y/(x-2) = -3/2
2y=6-3x
3x+2y-6=0
2008-05-25 21:47:18 補充：
001運算錯誤~
002 找c 可省 他用 slope- intercept form
我用point slope form
2008-05-26 4:43 am
let the equation be y=mx+c
slope of 2x-3y+5=0 is 2/3
slope of L=-1/2/3=-3/2
x-intercept=2
-c/m=2
-c/-3/2=2
c=3
the required equation
y=(-3/2)x+3
2y=-3x+6
3x+2y-6=0
slope of 2x-3y+5=0 is 2/3
slope of L=-1/2/3=-3/2
x-intercept=2
-c/m=2
-c/-3/2=2
c=3
the required equation
y=(-3/2)x+3
2y=-3x+6
3x+2y-6=0
2008-05-26 3:55 am
直线L斜率=-3/2
直线L方程:
(x-2)=-3/2 (y-0)
2(x-2)=-3y
2x 3y-2=0
直线L方程:
(x-2)=-3/2 (y-0)
2(x-2)=-3y
2x 3y-2=0
收錄日期: 2021-04-23 20:33:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080525000051KK02744