✔ 最佳答案
Given that the displacement of P at time t is s=15t+6t²-t³
Let f(t) be the s at time t,so
f(t)=15t+6t²-t³
As f(0)=0, s=0 when t=0,
the average velocity over the first t seconds equals s/t
s/t=f(2)/2
s/t=[15(2)+6(2)²-(2)³]/2
s/t=23
Thefore, the average velocity of P over the first 2 seconds is 23m/s
(b)
Given that the displacement of P at time t equals s=15t+6t²-t³
From (a), f(t)=s=15t+6t²-t³
ds/dt=v=f ’(t)=d(15t+6t²-t³)/dt
ds/dt=v=f ’(t)=-3t²+12t+15
When v=0, P comes to instantaneous rest
v=0
-3t²+12t+15=0
(t+1)(t-5)=0
t=-1 or t=5
As t=-1 is meaningless, P comes to instantaneous rest at t=5
Therefore, when P comes to instantaneous rest,
s=f(5)
s=15(5)+6(5)²-(5)³
s=100
The value of s when P comes to instantaneous rest is 100
(c)
From (a) and (b),
s=f(t)=15t+6t²-t³
v=f ’(t)=3t²+12t+15
dv/dt=a=f"(t)=d(-3t²+12t+15)/dt
dv/dt=a=f"(t)=-6t+12
When the acceleration of P is instantaneously zero, a=0
a=0
-6t+12=0
t=2
Therefore, the acceleration of P is instantaneously zero at t=2
v=f ’(2)
v=-3(2)²+12(2)+15
v=27
The velocity of P when its acceleration is instantaneously zero is 27m/s