dy/dx y=(3x-4)^2 (3x+2)^2

2008-05-25 11:55 pm
y=(3x-4)^2 (3x+2)^2 怎樣d?

回答 (3)

2008-05-26 3:36 am
✔ 最佳答案
AS follow AS~~~~~~~~
AS follow AS~~~~~~~~

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2008-05-26 12:14 am
係 dy/dx= lim(delta x-->0) [(3(x + delta x)-4)^2(3(x + delta x)+2)^2]-(3(delta x)-4)^2 (3(delta x)+2)^2/(delta x)
2008-05-26 12:12 am
y=(3x-4)^2 (3x+2)^2 = [(3x-4)(3x+2)]^2

=(9x^2-6x-8)^2

dy/dx= 2(9x^2-6x-8)*d(9x^2-6x-8)/dx << chain rule

=2(9x^2-6x-8)(18x-6)

=12(3x-1)(9x^2-6x-8)


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