dy/dx y=(3x-4)^2 (3x+2)^2
回答 (3)
係 dy/dx= lim(delta x-->0) [(3(x + delta x)-4)^2(3(x + delta x)+2)^2]-(3(delta x)-4)^2 (3(delta x)+2)^2/(delta x)
y=(3x-4)^2 (3x+2)^2 = [(3x-4)(3x+2)]^2
=(9x^2-6x-8)^2
dy/dx= 2(9x^2-6x-8)*d(9x^2-6x-8)/dx << chain rule
=2(9x^2-6x-8)(18x-6)
=12(3x-1)(9x^2-6x-8)
收錄日期: 2021-04-15 15:04:21
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