dy/dx y=(3x-4)^2 (3x+2)^2

AS follow AS~~~~~~~~
AS follow AS~~~~~~~~

圖片參考：http://i302.photobucket.com/albums/nn113/ken123572003/question5.jpg

係 dy/dx= lim(delta x-->0) [(3(x + delta x)-4)^2(3(x + delta x)+2)^2]-(3(delta x)-4)^2 (3(delta x)+2)^2/(delta x)

y=(3x-4)^2 (3x+2)^2 = [(3x-4)(3x+2)]^2

=(9x^2-6x-8)^2

dy/dx= 2(9x^2-6x-8)*d(9x^2-6x-8)/dx << chain rule

=2(9x^2-6x-8)(18x-6)

=12(3x-1)(9x^2-6x-8)