How can i Factor 8x^3 +27 ?
回答 (5)
2008-05-25 7:45 am
✔ 最佳答案
use sum of cubes.a^3 + b^3 = (a + b)(a^2 - ab + b^2)
(2x)^3 + 3^3 = (2x + 3)(4x^2 - 6x + 9)
2008-05-25 7:49 am
well 27 has a 3root, sorry forgot what it is actually called, so 3root(8x+3)
its the sum of perfect cube, use this formula:
a^3 + b^3 = (a + b) (a^2 - ab + b^2)
8x^3 + 27
= 2^3x^3 + 3^3
= (2x)^3 + 3^3
= (2x + 3) (4x^2 - 6x + 9)
its the sum of perfect cube, use this formula:
a^3 + b^3 = (a + b) (a^2 - ab + b^2)
8x^3 + 27
= 2^3x^3 + 3^3
= (2x)^3 + 3^3
= (2x + 3) (4x^2 - 6x + 9)
2008-05-25 7:47 am
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
8x^3 + 27
= (2x + 3)(4x^2 - 6x + 9)
8x^3 + 27
= (2x + 3)(4x^2 - 6x + 9)
2008-05-25 7:44 am
8x^3+27
=(2x)^3+(3)^3
=(2x+3)(4x^2-6x+9)
=(2x)^3+(3)^3
=(2x+3)(4x^2-6x+9)
2008-05-25 7:42 am
a³ + b³ = (a+b)(a²-ab+b²)
8x³ + 27
= (2x)³ + 3³
= (2x+3)((2x)² - 3(2x) + 3²)
= (2x+3)(4x²-6x+9)
8x³ + 27
= (2x)³ + 3³
= (2x+3)((2x)² - 3(2x) + 3²)
= (2x+3)(4x²-6x+9)
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