16y^2 -12y +2
^= exponent
what atre the facter of the following trinomial?
2008-05-23 3:08 pm
回答 (4)
2008-05-23 10:45 pm
16y^2 -12y + 2
2(8y^2 - 6y + 1)
ac = 8(1) = 8
Factors of 8 that add to - 6 are -4 & - 2
2(8y^2 - 4y - 2y + 1) {rewrite for grouping}
2[4y(2y - 1) - 1(2y - 1)]
2(4y - 1)(2y - 1)
2(8y^2 - 6y + 1)
ac = 8(1) = 8
Factors of 8 that add to - 6 are -4 & - 2
2(8y^2 - 4y - 2y + 1) {rewrite for grouping}
2[4y(2y - 1) - 1(2y - 1)]
2(4y - 1)(2y - 1)
2008-05-23 10:32 pm
16y^2 - 12y + 2
= 2(8y^2 - 6y + 1)
= 2(2y - 1)(4y - 1)
= 2(8y^2 - 6y + 1)
= 2(2y - 1)(4y - 1)
2008-05-23 10:21 pm
16y^2-8y-4y+2
8y(2y-1)-2(2y-1)
(2y-1)(8y-2)
(2y-1)4(y-1)
4(y-1)(2y-1)
8y(2y-1)-2(2y-1)
(2y-1)(8y-2)
(2y-1)4(y-1)
4(y-1)(2y-1)
收錄日期: 2021-05-01 10:32:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080523070810AA4Bf0v