6cos(2x) + 1 = 4
In other word, what is x...?
更新1:
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Solving equation (trig.)
2008-05-24 5:11 am
What is the principal root (in radians) of...
6cos(2x) + 1 = 4
In other word, what is x...?
6cos(2x) + 1 = 4
In other word, what is x...?
回答 (3)
2008-05-24 5:28 am
✔ 最佳答案
6cos(2x)+1=46cos(2x)=3
cos(2x)=1/2
2x=π/3，(5π)/3，(7π)/3 or (11π)/3
x=π/6，(5π)/6，(7π)/6 or (11π)/6
2008-05-24 5:53 am
6cos(2x) + 1 = 4
cos2x=1/2
2x=360°pi±60°
x=180°pi±30°
cos2x=1/2
2x=360°pi±60°
x=180°pi±30°
2008-05-24 5:26 am
6cos(2x) + 1 = 4
6cos(2x) = 3
cos(2x) = 3/6
cos(2x) = 1/2
2x=(2/3)pi+2k*pi
x=(1/3)pi+k*pi
6cos(2x) = 3
cos(2x) = 3/6
cos(2x) = 1/2
2x=(2/3)pi+2k*pi
x=(1/3)pi+k*pi
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