Quadratics: How can you convert 8y^2 - 2 = 0 into ax^2 + bx + c = 0 form?
2008-05-20 9:59 am
Well the question above is the part i didn't understand but the main question is to find the discriminant for 8y^2 - 2 = 0. If there's meant to be an easier way rather than trying to change the form...well, is there? =]
回答 (4)
2008-05-20 10:06 am
✔ 最佳答案
8y^2 - 2 = 08y^2 +0y -2 = 0
8 is your a, 0 is your b, -2 is your c...
Discriminant = b^2 − 4ac
0^2 - 4(8)(-2)
0 - (-64)
64 = Discriminant
2008-05-20 11:04 am
8y^2 - 2 = 0 into ax^2 + bx + c = 0 form:
8y^2 + 0y - 2 = 0
8y^2 + 0y - 2 = 0
2008-05-20 10:08 am
no term with y is there so the coeff. of y is 0
=>8y^2+(or -)0y-2=0
D=b^2-4ac
=0-4(8)(-2)
=64
=>8y^2+(or -)0y-2=0
D=b^2-4ac
=0-4(8)(-2)
=64
2008-05-20 10:07 am
Its 8Y^2 - 0Y - 2 = 0. What's the matter? A term is absent means, In maths, it is present with coefficient 0.
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