問一條好簡單既問題.. Identities
點解(x-y)^2唔等於x^2-y^2?
拆開左個括號唔係一樣架咩?
回答 (3)
✔ 最佳答案
(x-y)^2 = (x-y) * (x-y)
= x^2-xy-xy+y^2
= x^2-2xy+y^2
(x-y)^2
= (x-y)(x-y)
= x^2 - xy - xy + y^2
= x^2 - 2xy + y^2
唔等於x^2 - y^2。
如果
(x-y)^2 = x^2 - y^2
x^2 - 2xy + y^2 = x^2 - y^2
2y^2 - 2xy = 0
2y (y-x) = 0
y = 0 or y-x = 0
y = 0 or y = x
即係如果(x-y)^2 = x^2 - y^2,咁y就要等於0或者x。
你仲係唔信既代d數入去計:
例如:設 x = 7, y = 2
(x-y)^2
= (7-2)^2
= 5^2
= 25
x^2 - y^2
= 7^2 - 2^2
= 49 - 4
= 45
25唔等於45
所以(x-y)^2 唔等於 x^2 - y^2。
(x-y)^2
=(x-y)(x-y) ----- x同x乘左,,y同y乘左,,咁x同y都要乘架
=x^2-2xy y^2 ----- x乘左-y等於-xy,,兩個-xy加埋就等於-2xy
另外,,因為-y乘-y,,負負會得正,,所以乘完出黎會係
正y而唔係-y
希望幫到你=)
參考: 自己=)
收錄日期: 2021-04-13 15:35:31
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