What is the answer to the quadratic equation10y^2 - y - 65 = 0?

10y^2 - y - 65 = 0
(2y + 5)(5y - 13) = 0

2y + 5 = 0
2y = -5
y = -5/2 (-2.5)

5y - 13 = 0
5y = 13
y = 13/5 (2.3)

∴ y = -5/2 (-2.5) , 13/5 (2.3)

y = [ 1 ± √ (1 + 2600 ) ] / 20
y = [ 1 ± √ (2601) ] / 20
y = [ 1 ± 51 ] / 20
y = 52 / 20 , y = - 50 / 20
y = 13/5 , y = - 5/2

If you are allowed to use a calculator:

,/ represents square root

Put that into the quadratic formula

y = -b +or- ,/(b^2 - 4ac)
_______________
2a

Where 10y^2 - y - 65 = 0
This is a b c

So a = 10, b = 1 and c = 65

Put them into your formula and you should get two answers (because there is a +or- sign, you need to get 2 answers.)

answer is
x=2.5, 2.6