Factorise: 2x^2 - 4x + 2?

2x² - 4x + 2
= 2(x² - 2x + 1)
= 2(x-1)²

( 2x - 2 )( x - 1 )

First, you find the highest common factor among the three:
2(x^2 - 2x + 1)

Next, you find out if the algebraic expressions are applicable:
(a - b)(a + b) = a^2 - b^2
(a - b)^2 = a^2 - 2ab + b^2
(a + b)^2 = a^2 + 2ab + b^2

In this case, since there are 3 terms and a minus sign, it should be the third one:
2(x - 1)^2

Anyway, if the algebraic expressions are not applicable, you should try out the cross-method (it is very useful).

... CLEZ1 is wrong anyway

= 2(x^2-2x+1)
x^2-2x+1 is a perfect square so = (x-1)(x-1)
= 2(x-1)(x-1)

2x² - 4x + 2
= 2(x² - 2x + 1)
= 2(x-1)²

Factor out GCF (i.e. 2x) 2x (x - 2) So if you are looking for roots of polynomial, you get 2x^2 - 4x = 0 2x (x - 2) = 0 x = 0, x = 2 Mαthmφm

2x^2 - 4x + 2
= 2(x^2 - 2x + 1)
= 2(x - 1)(x - 1)
= 2(x - 1)^2

2x² - 4x + 2, can be written as:
2x² - 2x - 2x + 2, which equals:
2x(x - 1) -2(x - 1). So, the factors are:
2(x - 1)(x - 1) OR (2x - 2)(x - 1). Hope my answer is useful.

2 (x² - 2x + 1)
2 (x - 1) (x - 1)
2 (x - 1)²

The answer should be-
(2x-2)(x-1)
After you open the bracket,You will get back 2x^2-2x-2x+2=2x^2-4x+2