數學方程問題x1！！！！～～～～急！！！１０分呀．

2008-05-20 5:07 am

1.The total number of tickets sold for a school play was 450 and the money received for the ticktes sold was 42600. If adult's tickets were sold at 47.5 each and student's tickets were sold at 45 each, how many tickets of each kind were sold?

更新1:

sor我打錯左句句子= =" 應該係: If adult's tickets were sold at $7.5 each and student's tickets were sold at $5 each sorrry呀..

更新2:

順便講一講: 可唔可以只係用1個未知數(x,y,z等)黎計呢條數呀.." 我唔想用2個代數黎計,因為我學校都未教..(我宜家f.1昨wor) thx a lot~ 以後有d咩補充我會再講的,所以請答既人兄不時番黎睇

回答 (2)

用戶19657

2008-05-20 5:17 am

✔ 最佳答案

Let x adult tickets were sold
Let y student tickets were sold

x+y=450
47.5x+45y=42600

2008-05-19 21:23:12 補充：
1. 450-y=x
sub x into 2nd eq
x=8940
y=-8490

2.45(x+y)=450(45)

47.5x-45x+45y-45y=42600-20250
x=8940
y=-8490

所以請問是否你的題目數字有錯?
我計了很多次及用不同的方法都是這樣啊~

2008-05-25 20:57:06 補充：
可以ge~
Let x adult tickets were sold
然後寫條式
so,450-x student tickets were sold

$7.5x+$5(450-x)=42600
咁ok嗎??

我係回答者~已經改左4字做$ 啦~
你用我之前的方法比較安全，有可能有時會計唔到ga~

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_TAK''

2008-05-20 5:14 am

let $X and$Y be the prices of the first and second tickets respectively.

X+ Y=450.....(1)

47.5X+45Y=42600.....(2)

（２元一次）　　

參考: 博士

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