Can you simplify this?

We can use the indices law where (a^b)^c = a^(b*c) and everything inside the brackets is raised to that power.

(2w ²t)^4
= (2^4)(w^(2*4))(t^4)
= 16 w^8 t^4

*βω*

(2 w² t)^4
2^4 w^8 t^4
16 w^8 t^4

(2w^2t)^4

= [(2*w^2* t)(2*w^2* t)]^2

= [2*w^2*t*2*w^2*t]^2

= [ 4*w^4*t^2]^2

= [4*w^4*t^2*4*w^2*t^2]

= 16*w^8*t^4

Another approach is:

(2*w^2*t)^4

= (2^4)*(w^2)^4*(t)^4

= 16*w^8*t^4 the same as before

I have use * as the multiplication sign and put it in for clarity. Not needed when you write these out clearly.

(2w^2t)^4

that means raise everything in the brackets to the power 4

which gives

2^4.(w^2)^4.t^4

ie

2^4.w^8.t^4

ie

16t^4.w^8

(conventional to put variables in alphabetical order)

(2w^2t)^4
= (2^4)[w^(2 * 4)](t^4)
= (16)[w^8](t^4)
= 16w^8t^4