2^6/3
8^8/4
16^1/2
4^-3
Key- ^ = to the power of.
How do I write these as powers of 2?
2008-05-18 2:53 pm
回答 (6)
2008-05-18 2:59 pm
✔ 最佳答案
2^2 (2^3)^2=2^6
(2^4)^1/2= 2^2
(2^2)^-3= 2^(-6)
2008-05-18 10:30 pm
1)
2^(6/3)
= 2^2
= 4
2)
8^(8/4)
= 8^2
= 64
3)
16^(1/2)
= 屉16
= ±4
4)
4^-3
= 1/4^3
= 1/64
2^(6/3)
= 2^2
= 4
2)
8^(8/4)
= 8^2
= 64
3)
16^(1/2)
= 屉16
= ±4
4)
4^-3
= 1/4^3
= 1/64
2008-05-18 10:04 pm
2^6/3 = ³â2^6
= ³â2^3^2 = 2² = 4
8^8/4
= 2^3^2 = 2^6 = 64
16^1/2
= 2^4^(1/2) = 2^2 = 4
4^-3
= 2^2^(–3) = 2^(–6)
= 1/2^6 = 1/64
---------
= ³â2^3^2 = 2² = 4
8^8/4
= 2^3^2 = 2^6 = 64
16^1/2
= 2^4^(1/2) = 2^2 = 4
4^-3
= 2^2^(–3) = 2^(–6)
= 1/2^6 = 1/64
---------
2008-05-18 10:02 pm
2^6/3
(no idea to that)
8^8/4
first, you need to express 8 and 4 as a power of two..that would be 2^3 , then your expression would look like [(2^3)^8]/[2^2]
and then simplify,that would be: (2^24)/(2^2), apply law on dividing exponents, that would be 2^22
16=2^4
(2^4)/2=2^3
no idea for the last one
(no idea to that)
8^8/4
first, you need to express 8 and 4 as a power of two..that would be 2^3 , then your expression would look like [(2^3)^8]/[2^2]
and then simplify,that would be: (2^24)/(2^2), apply law on dividing exponents, that would be 2^22
16=2^4
(2^4)/2=2^3
no idea for the last one
2008-05-18 10:01 pm
Isn't 6/3 = 2? Then first is 2^2 = 4. Same for second, it is 8^2 = 16, Power is 1/2 means the square root. So third is sq rt of 16 which is 4 or -4. Negative power means reciprocal so 4^-3 = 1/ 4^3 = 1/64.
2008-05-18 10:00 pm
2^6/3 = 2^2
8^8/4 = 8^2 = (2^3)^2 = 2^6
16^1/2 = (2^4)^1/2 = 2^2
4^-3 = (2^2)^-3 = 2^-6 = 1/2^6
8^8/4 = 8^2 = (2^3)^2 = 2^6
16^1/2 = (2^4)^1/2 = 2^2
4^-3 = (2^2)^-3 = 2^-6 = 1/2^6
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