How do I write these as powers of 2?

2^2

(2^3)^2=2^6


(2^4)^1/2= 2^2


(2^2)^-3= 2^(-6)

1)
2^(6/3)
= 2^2
= 4

2)
8^(8/4)
= 8^2
= 64

3)
16^(1/2)
= ±√16
= ±4

4)
4^-3
= 1/4^3
= 1/64

2^6/3 = ³√2^6
= ³√2^3^2 = 2² = 4

8^8/4
= 2^3^2 = 2^6 = 64

16^1/2
= 2^4^(1/2) = 2^2 = 4

4^-3
= 2^2^(–3) = 2^(–6)
= 1/2^6 = 1/64
---------

2^6/3
(no idea to that)

8^8/4
first, you need to express 8 and 4 as a power of two..that would be 2^3 , then your expression would look like [(2^3)^8]/[2^2]
and then simplify,that would be: (2^24)/(2^2), apply law on dividing exponents, that would be 2^22

16=2^4
(2^4)/2=2^3

no idea for the last one

Isn't 6/3 = 2? Then first is 2^2 = 4. Same for second, it is 8^2 = 16, Power is 1/2 means the square root. So third is sq rt of 16 which is 4 or -4. Negative power means reciprocal so 4^-3 = 1/ 4^3 = 1/64.

2^6/3 = 2^2

8^8/4 = 8^2 = (2^3)^2 = 2^6

16^1/2 = (2^4)^1/2 = 2^2

4^-3 = (2^2)^-3 = 2^-6 = 1/2^6