[ (x^-4) / 9 ] ^-(1/2)
How do yous simplify it ?
thanks
Algebra help ?
2008-05-18 7:36 am
回答 (8)
2008-05-18 7:52 am
✔ 最佳答案
= {(x^-4)^-1/2} / 9^-1/2= x^2 / (1/3)
=3x^2
2008-05-18 8:19 am
[ x^(- 4) / 9 ]^(-1/2)
x² / 9^(-1/2)
x² 9^(1/2)
3 x²
x² / 9^(-1/2)
x² 9^(1/2)
3 x²
2008-05-18 8:10 am
[(x^-4)/9]^(-1/2)
= √{[x^(-4 * -1)]/[9^-1]}
= √{[x^4]/[1/9]}
= √{[x^4][9]}
= √{9x^4}
= 3x^2
= √{[x^(-4 * -1)]/[9^-1]}
= √{[x^4]/[1/9]}
= √{[x^4][9]}
= √{9x^4}
= 3x^2
2008-05-18 7:50 am
Hi there ,
The answer is 3x^2 . Very simple
The answer is 3x^2 . Very simple
2008-05-18 7:43 am
[ (x^(-4)) / 9 ] ^(-1/2)
= [ 9/(x^(-4)) ] ^(1/2)
= [(9)^(1/2) ]/ [(x^(-4))^(1/2)]
= 3 / (x^(-2))
= 3 x^2
Note: a^(-n) = 1/(a^n)
= [ 9/(x^(-4)) ] ^(1/2)
= [(9)^(1/2) ]/ [(x^(-4))^(1/2)]
= 3 / (x^(-2))
= 3 x^2
Note: a^(-n) = 1/(a^n)
2008-05-18 7:42 am
You apply the power of -1/2 to both parts of the equation:
(x^-4) ^-(1/2) / 9^-(1/2)
then you can multiply the powers of x and invert the 9 (getting rid of the -ve power)
x^2* 9^(1/2)
3x^2
(x^-4) ^-(1/2) / 9^-(1/2)
then you can multiply the powers of x and invert the 9 (getting rid of the -ve power)
x^2* 9^(1/2)
3x^2
2008-05-18 7:40 am
[ (x^-4) (3)^-2) ] ^-(1/2)
= (x^2) 3^1
= 3 x^2
= (x^2) 3^1
= 3 x^2
2008-05-18 7:38 am
3x^2
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