2x^2 - 2x - 12?

factor out the two to get:

2(x^2-x-6)

now it's probably easier to look at:

2(x-3)(x+2)

2(x^2 - x - 6) = 2(x-3)(x+2)

Factor Completely 2x2-2x-12

2(x² - x - 6)
2(x - 3)(x + 2)

=2(x^2 - x - 6)
=2(x-3)(x+2)

2(x^2 - x - 6) = 2(x-3)(x+2)

2x^2 - 2x - 12

= 2(x^2 - x- 6)

= 2( x -3) (x+2)

2x^2 - 2x - 12
= 2(x^2 - x - 6)
= 2(x + 2)(x - 3)

2(x^2 - x - 6) = 2(x - 3)(x + 2)

Take out the 2 as common
2x^2 - 2x - 12
= 2(x^2 - x - 6)
And then factorise
= 2(x - 3)(x + 2)

*βω*